WebIf we run this program, we can see that the Go compiler issues a warning in the loop: loop variable i captured by func literal. The variable in the loop gets referenced in the function we defined—the creation loop of the goroutines is quicker than goroutines executing, and the result is that the loop finishes before a single goroutine is ... Webok := true for _, v := range values { if ok { go func() { fmt.Println(v) done <- true }() } } then go vet prints nothing. Looking at the vet source code, checkRangeLoop can just judge a go or defer statement for body to see whether a variable is capture, which means vet will be failed if it exists condition sentence before a go or defer statement
go vet - loop variable i captured by func literal - Stack Overflow
Web7 de jul. de 2024 · $ go vet main.go main.go:24:16: loop variable i captured by func literal 我们可以将这个工具集成到IDE中，让我们在写代码的时候能自动对代码进行检查，用于快速发现这类的问题。 Goland设置. Goland中可以在 Preferences / Tools / File Watchers中添加一个golangci-lint的工具 Web22 de jul. de 2015 · go version devel +4df6dcb Wed Jul 22 16:12:06 2015 -0400 linux/amd64 Vet complains that "v" is captured by this loop; it isn't: package main import ... package main import "fmt" func main ... % go tool vet main.go main.go:13: range variable v captured by func literal The text was updated successfully, but these errors were ... how to pair ilive speaker
GO loop variable captured by func literal - CSDN博客
Web30 de ago. de 2013 · Regarding your comment on the for loop, ... The for loop is still very silly. It overwrites the same variable on each iteration and the end result is to get only … Web22 de jul. de 2024 · Loop variable 'item' captured by func literal 解决方案 for i := 0; i < 10; i++ { i0 := i go func() { fmt.Println(i0) } () } 1 2 3 4 5 6 输出： 1 0 2 9 7 3 8 4 2 1 2 3 4 5 6 … WebPass loop variable i into function. go func(i int) { defer wg.Done() sleep() log.Println(i) }(i) Or declare a local variable. wg.Add(1) i := i go func() { defer wg.Done() sleep() log.Println(i) }() how to pair iclever keyboard